Answer:
g(x) = x^2 + 11x - 60
(a=1, b=11, c=-60)
To solve this quadratic equation we need to find the discriminant:
discriminant= b^2 - 4ac
= (11)^2 - 4(1)(-60)
=121 - (-240) = 121+240 =361
(if discriminant<0 then equation has no real root
if discriminant=0 then equation has 1 real root
if discriminant>0 then equation has 2 real roots)
Here we have discriminant=361>0 so we have 2 real roots:
x1=(-b-redical discriminant) / 2a
and x2=(-b+redical discriminant) / 2a
x1= (-11-redical(361)) / 2(1)
=-15
x2= (-11+redical(361)) / 2(1)
=4
So we get the two roots x= -15 and x= 4
To write the quation in factorized form:
x= -15 means that x+15=0
x= 4 means that x-4=0
Therefore g(x)= (x+15)(x-4)
D is the correct answer
HOPE THIS HELPS :)