Answer:
See below.
Explanation:
If you have the vertex form of the equation, shown below, the vertex is at (h, k) so the y coordinate of the vertex is k:
y = a(x - h)^2 + k.
If the equation of the parabola is in standard form you can find it by converting to vertex form;
Find the vertex of the parabola y = x^2 - 2x - 10:-
y = x^2 - 2x - 10 Completing the square:
y = (x - 1)^2 - 1 - 10
y = (x - 1)^2 - 11
The vertex is at (1, -11).
y -coordinate is -11.