Question

Keenan wants to make a paperweight at pottery class. He designs a pyramid-like model with a base area of 808080 square centimeters and a height of 7.57.57, point, 5 centimeters. The density of the clay he is using is 1.71.71, point, 7 grams per cubic centimeter.

What is the weight of Keenan's paperweight?

Answer 1

It is 340

Explanation:

Answer 2

The weight of Keenan's paperweight is 3.33 N.

Explanation:

Givens

• The base area is 80 square centimeters.
• The height of the pyramid is 7.5 centimeters.
• The density of the pyramid is 1.7 grams per cubic centimeters.

First, we find the volume of the figure.

`V=(1)/(3) (B * h)`

Where
`B=80cm^(2)` and
`h=7.5 cm`.

Replacing values, we have

`V=(1)/(3)(80)(7.5)=200cm^(3)`

The density is defined as

`\rho=(m)/(V)`

Where we need to find the mass
`m`, we already know that
`\rho=1.7 \ gr/cm^(3)` and
`V=200cm^(3)`. Replacing these values, and solving for
`m`

`1.7=(m)/(200)\\ m=1.7(200)=340 \ gr`

Then, we use the weight definition, which is

`W=mg`

Where
`m=340 \ gr=0.34 \ kg` and
`g=9.81 m/sec^(2)`. Replacing these values, we have

`W=0.34(9.81)\\W=3.33 N`

Therefore, the weight of Keenan's paperweight is 3.33 N.