Question

The first hiker has gone 125 ft and hikes at a rate of 1.2 ft per second. The second hiker has gone 10ft and hikes 2.6 ft per second. after about how many seconds will the hikers have gone the same distance

82 seconds
90 seconds
73 seconds
67 seconds

Answer 1

It will take approximately 82 seconds for the two hikers to have traveled the same distance. This is found by setting up and solving an equation that represents the distance each hiker has traveled over time.

Step-by-step explanation:

To determine after how many seconds the two hikers will have gone the same distance, we can set up an equation where the first hiker's distance is equal to the second hiker's distance.

Let t represent the number of seconds after which they will have covered the same distance. The first hiker starts at 125 ft and hikes at a rate of 1.2 ft/s. The second hiker starts at 10 ft and hikes at a rate of 2.6 ft/s.

First Hiker's distance = 125 + 1.2t

Second Hiker's distance = 10 + 2.6t

We set these two expressions equal to each other to find t:

125 + 1.2t = 10 + 2.6t

Solving for t:

1.2t - 2.6t = 10 - 125

-1.4t = -115

t = -115 / -1.4

t = 82.14 seconds

Therefore, it will take approximately 82 seconds for the hikers to have gone the same distance.

0

Answer 2

82 seconds

Step-by-step explanation:

(1.2*82)+125=223.4

(2.6*82)+10=223.2

These are the closest. If you are estimating this is the right answer