Given↷
- PE of products⇢ 55kJ
- PE of reactants⇢30kJ
- Activation energy⇢65kJ
To find↷
- Total change in enthalpy of the reaction
Answer↷
Solution↷
we know that,
AᵣH = (Sum of enthalpies of products)-(Sum of enthalpies of reactants)
AᵣH = 55kJ - 30 kJ
AᵣH = 25kJ
or
AᵣH =( Activation Energy-Reactant energy) +( Activation Energy-product energy)
AᵣH =(65kJ -30kJ) +(65kJ-55kJ)
- Since there's a degrade , we'll consider the PE of product as -ve
AᵣH = 35kJ - 10kJ
AᵣH = 25kJ