Answer:
The probability that the sample proportion is more than 0.35 believe movie trailers reveal too much is 0.1539.
Explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
![\mu_(\hat p)=p](https://img.qammunity.org/2021/formulas/mathematics/college/mruuwakwsspmc2v3pjp0tuu9b0iyrrfz34.png)
The standard deviation of this sampling distribution of sample proportion is:
![\sigma_(\hat p)=\sqrt{(p(1-p))/(n)}](https://img.qammunity.org/2021/formulas/mathematics/college/pbpnjezz5com05nodxdjp5bgchns8g2nx6.png)
The information provided is:
p = 0.32
n = 250
Since the sample size is quite large, i.e. n = 250 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by a Normal distribution.
Compute the probability that the sample proportion is more than 0.35 believe movie trailers reveal too much as follows:
![P(\hat p>0.35)=P((\hat p-\mu_(\hat p))/(\sigma_(\hat p))>\frac{0.35-0.32}{\sqrt{(0.32(1-0.32))/(250)}})](https://img.qammunity.org/2021/formulas/mathematics/college/3mhcphuhq3cytnw7mevkariawlk54nqc6v.png)
![=P(Z>1.02)\\=1-P(Z<1.02)\\=1-0.84614\\=0.15386\\\approx 0.1539](https://img.qammunity.org/2021/formulas/mathematics/college/8wboci7l3yjt50nxq89rddftwyl22kp367.png)
Thus, the probability that the sample proportion is more than 0.35 believe movie trailers reveal too much is 0.1539.