Answer:
For the deform two cylinder specimen the answer is 62.65% CW,The second specimen is 7.33 mm
Step-by-step explanation:
Solution
Now,
Let calculate the percentage of the cold work to be carried out to deform the two cylinder specimens to have the same hardness.
% CW = A₀ - Ad /A₀ * 100
=πr²₀ - πr²d /πr²₀ * 100
so,
r²₀ - r²d/ r²₀ * 100
= 18² - 11²/18² * 100
= 324 -121/324 * 100
= 62.65% CW
Now,
We calculate for the deformed radius of the second specimen for the same direction
so,
r₂ = r₀√ 1 - %CW /100
= 12 √ 1 - 6265/ 100
= 12 * 0.6111
r₂ = 7.33 mm