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In the calibration of an ammeter, using Faraday's law of electrolysis, the ammeter is kept constant at 1.2A (ampere). If 0.99g of copper is deposited in 40 minutes, find the correction to be applied to the ammeter. (Take Z = 0.00033gc^-1).​

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Answer:

dont you have to times it to get what you need

Step-by-step explanation:

User Icguy
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