144k views
7 votes
Please help this is very important

Please help this is very important-example-1

1 Answer

10 votes

4. sector angle = 120°

area of sector = 120/360* π*r^2

= 1/3 π *36 = 12π = 37.69 cm^2

area of isosceles ∆ = .5*36*sin 120 = 15.58cm^2

area of shaded portion = 37.69 - 15.58= 22.11 cm^2

5. sector area = 90/360 * π * 64 = 16π ft^2

area of right ∆ = 1/2*64= 32ft^2

shaded portion area = 16π-32 = 18.26ft^2

6. sector area = 60/360 π 36 = 6π m^2

triangle area = √3/4 * 36 = 9√3 m^2

shaded area = 18.84 - 9√3 = 3.26 m^2

7. sector area = 45/360*π*18^2 = 40.5 π yd^2

8. sector area = 90/360*π*16 = 64π cm^2

9. sector area = 60/360 * π * 169 = 28.16π m^2

10. sector area = 135/360*π*64 = 24π cm^2

1. circle area = π*5.5^2 = 30.25π cm^2

2. circle area = π*0.85*.85 = .7225π ft^2

3. circle area = π * 1/9 in^2

User Nikunj Satasiya
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories