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Find the limit as xxx approaches negative infinity.

Find the limit as xxx approaches negative infinity.-example-1
User Iddo
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1 Answer

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Answer:


\displaystyle \lim_(x \to -\infty) (3x)/(√(16x^2 - 9x)) = (3)/(16)

General Formulas and Concepts:

Calculus

Limits

Coefficient Power Method:
\displaystyle \lim_(x \to \pm \infty) (ax^n)/(bx^n) = (a)/(b)

Explanation:

We are given the limit:


\displaystyle \lim_(x \to -\infty) (3x)/(√(16x^2 - 9x))

We can see that if we "simplify" the radical, resulting in a degree of 1. Let's use Coefficient Power Method to evaluate the limit:


\displaystyle \lim_(x \to -\infty) (3x)/(√(16x^2 - 9x)) = (3)/(16)

And we have our answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

User Subarata Talukder
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