Question

The current in the wires of a circuit is 120.0 milliAmps. If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance), then its new current would be _____ milliAmps.

Answer 1

Doubling the voltage across a circuit with a constant resistance will result in a doubling of the current through the circuit.

Step-by-step explanation:

According to Ohm's Law, the current in a circuit is directly proportional to the voltage applied across it, and inversely proportional to its resistance. Doubling the voltage across the circuit would result in a doubling of the current through the circuit, given that the resistance remains constant.

For example, if the current in the wires of a circuit is initially 120.0 milliAmps, doubling the voltage would result in a new current of 240.0 milliAmps.

Answer 2

Its new current will be 240.0milliAmps

Step-by-step explanation:

According to ohms law,

V = IR

V is the supply voltage in a circuit

I is the current

R is the resistance

If the current in the wires of a circuit is 120.0 milliAmps, the voltage will be:

V1 = 120R1

R1 = V1/120...(1)

If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance),

V2 = 2V1

V2 = IR2

2V1 = IR2

R2 = 2V1/I ... (2)

Since there are no changes in resistance

R1 = R2

Equating 1 and 2, we have:

V1/120 = 2V1/I

1/120 = 2/I

Cross multiplying

I = 2×120

I = 240milliAmps