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Find the minimum or maximum of the function y=−x^2+4x−5.

1 Answer

2 votes

Answer:

maximum value : y = - 1 at (2, -1)

No local minimum

Explanation:

The function y=−x^2+4x−5. is a downward opening parabola.

The local maximum is at the vertex

y = - (xx - 4x ) - 5

y = - (xx - 4x +4 - 4) - 5

y = - (xx - 4x + 4) + 4 - 5

y = -(x - 2)^2 - 1

vertex at (2, -1)

User Jameem
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