Question

A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger? (DECIMAL FORM)

Answer 1

0.07

Explanation:

First, add up all the numbers. This will be the denominator.

4+2+3=9

There are 9 pieces of candy.

Since you are randomly choosing two times you will have to multiply two fractions.

There are
`(2)/(9)` M&M's, and
`(1)/(3)` Butterfingers (You simplify)

Now you multiply these.

`(2)/(9)`×
`(1)/(3)`=
`(2)/(27)`

Now make this into a decimal. To do this divide 2 and 27. which is approximately 0.07.