Question

When 0.250 moles of a gas is placed in a container at 298K, it exerts a pressure of 0.92 atm. What is the volume of the container? PV = nRT R = 0.0821 L·atm/mol·K options: 0.12L 0.55L 6.6L 8.3L

Answer 1

Step-by-step explanation:

PV = nRT

We are to get the answer for the volume. Hence we make V the subject of the formula.

V = nRT/P

Where n= 0.250, R= 0.0821, P= 0.92 and T = 298

V = (0.250×0.0821×298)÷0.92

V = 6.11645÷0.92

V = 6.64

V = 6.6L