Question

20)

For which values of x is the inequality 3(1 + x) < x + 6 true?
0 & 1
2 & 3
4&5
6 & 7

Answer 1

0 & 1

Explanation:

3(1 + x) < x + 6

Distribute

3x+3 < x+6

Subtract x from each side

3x+3-x < x+6-x

2x+3 <6

Subtract 3 from each side

2x+3-3 <6-3

2x <3

Divide each side by 2

2x/2 <3/2

x <3/2