Question

525 grams of tin(II) fluoride are dissolved in water to create a solution with a total

volume of 3.50 L. What is the molarity of the solution?

Answer 1

MOLARITY = 0.9554 mol/dm3

Step-by-step explanation:

525 grams of SnF2 in 3.50 L of wate

To obtain the molarity, calculate the concentration in g/dm3 and then concentration in mol/dm3

Concentration in g/dm3 = 525 g/ 3.50 L

= 525g/ 3.50 dm3

= 150g/dm3 of SnF4

Concnetration in mol/dm3

concentration in mol/dm3 = concentration in g/dm3 / Relative molecular mass of SnF2

RMM of SnF2 = ( 119 + 19*2) = 157 g/mol

= 150g/dm3 / 157g/mol

= 0.9554 mol/dm3 of solution.

The molarity of the solution is therefore 0.9554mol/dm3