Answer: V' = 1.514m/s
Explanation: Given the Impulse-Momentum Theorum, this is a description of an INELASTIC Collision. When you hug, you stick, making it inelastic.
Formula: m1xV1+m2xV2= pTotal, or total momentum
m1=60kg
V1=1.5m/s
m2=45kg
V2=2.2m/s
so (60)(1.5)+(45)(2.2)=159 kgm/s
To find the Resultant velocity of the lover(s) - plural (signalling inelastic)
you would take the sum of the m1+m2, which is 105kg-> then create the equation 159/105, which is the total momentum divided by the total mass, which would equate to the resultant velocity of an inelastic collision.
Hope this helped.