Question

If a circle has a radius of \sqrt{13}

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and is centered at (9, -3), what is the equation of this circle?

Answer 1

(x-9)^2 + (y+3)^2 = 13

Explanation:

The equation of a circle can be written as

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x-9)^2 + (y--3)^2 = (sqrt(13))^2

(x-9)^2 + (y+3)^2 = 13