Answer:B. x=-5 and x=3
Explanation:
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Answer:
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(x + 2)2 – 2(x + 2) – 15 = 0
let : t= x+2
t²-2t-15 =0
(t-5)(t+3)=0
t-5=0 or t+3=0
t=5 or t=-3
but : t =x+2
if : t=5 x+2 =5 so : x=3
if : t= -3 x+2 = -3 so : x= -5
conclusion two solutions : 3 , -5
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