Answer:
80% confidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is [0.240 , 0.298].
Explanation:
We are given that an automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars over domestic.
Suppose a sample of 390 new car buyers is drawn. Of those sampled, 105 preferred foreign over domestic cars.
Firstly, the pivotal quantity for 80% confidence interval for the population proportion is given by;
P.Q. =
~ N(0,1)
where,
= sample proportion of car buyers who preferred foreign over domestic cars =
= 0.27
n = sample of new car buyers = 390
p = population proportion
Here for constructing 80% confidence interval we have used One-sample z proportion statistics.
So, 80% confidence interval for the population proportion, p is ;
P(-1.2816 < N(0,1) < 1.2816) = 0.80 {As the critical value of z at 10% level
of significance are -1.2816 & 1.2816}
P(-1.2816 <
< 1.2816) = 0.80
P(
<
<
) = 0.80
P(
< p <
) = 0.80
80% confidence interval for p = [
,
]
= [
,
]
= [0.240 , 0.298]
Therefore, 80% confidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is [0.240 , 0.298].