Answer:
Volume is 3.36L
Step-by-step explanation:
Mass = 5.32g
Molar mass = 35.5g/mol
Pressure at STP = 1atm
Temperature at STP = 273.15K
Volume = ?
R = 0.082J/K.mol
From ideal gas equation,
PV = nRT
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
n = mass / molar mass
n = 5.32 / 35.5
n = 0.15moles
PV = nRT
V = nRT / P
V = (0.15 * 0.082 * 273.15) / 1
V = 3.359L
V = 3.36L
The volume of 5.32g of Chlorine at STP is 3.36L