Answer:
The parameter p is 18.
Explanation:
The given equation is
![x^(2) =-2py](https://img.qammunity.org/2021/formulas/mathematics/high-school/t2rujwonijpfo29hqepd1b5orzze312qm6.png)
This equation represents a parabola, where
is the main parameter.
Also, we know that the point
is on the parabola, which means we can use it to find the parameter
.
![x^(2) =-2py\\(-6)^(2) =2p(1)\\36=2p\\p=(36)/(2)\\ p=18](https://img.qammunity.org/2021/formulas/mathematics/high-school/s2wlzupl9pe021fj6rwavt8fkemjfu1pxr.png)
Therefore, the paremeter
is 18.