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3 votes
An isosceles triangle has area of 110 ft. If the base is 14 ft, what is the length of each leg? Round your

answer to the nearest tenth.
Time Running
Artemot du May 22
1 Hour, 9 Minutes
21 ft
14.8 ft
17.2 ft
442.9 ft

User Dalvtor
by
8.1k points

2 Answers

4 votes

Answer:

h=15,7 ft

l1=19.8

l2=l1=19.8

Explanation:

A=(b×h)/2

110=x×14/2

x×14=220

x=220/14=15,7

h=15.7 ft

l=rad(144+246.7)=19,8

l1=l2=19,8

User Sasith
by
8.3k points
5 votes

Answer:

Explanation:

Area = 1/2*b*h

110 = 1/2 * 14 * h

15.714 = h

Pythagoren th

c^2 = a^2 + b^2

c^2 = 7^2 + (15.714)^2

c^2 = 49 + 246.93

c^2 = 295.93

c = 17.2

User Besi
by
7.9k points

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