Question

How many grams of NaOH are produced with the reaction of 5.00 moles of water?

Answer 1

Step-by-step explanation:

6.90 mol x grams

2As + 6NaOH = 2Na3AsO3 + 3H2

6 mol 2 mol

192 g/mol

6.90 mol NaOH x 2 mol Na3AsO3/6 mol NaOH== 2.3 mol Na3AsO3

2.3 mol Na3AsO3 x 192 g/mol = 442 g Na3AsO3