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What is the pH of a 5.41g of HNO3 in 7L of solution? (mass of HNO3=63.02g)

1 Answer

7 votes

Answer:

1.9

Step-by-step explanation:

Let us call to mind the formula

m/M= CV

Where

m= mass of the solute= 5.41 g

M= molar mass of the solute = 63.02g

C= concentration of the solution (the unknown)

V= volume of the solution = 7L

5.41 / 63.02g = 7C

0.0858= 7C

C= 0.0858/7

C= 0.01226 molL-1

[H^+]= [HNO3]= 0.01226 molL-1

pH= - log [H^+]

pH= -log(0.01226)

pH= 1.9

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