Question

The axis of symmetry for the graph of the function f(x)=3x^2+bx+4 is x= 3/2. what is the value of b

Answer 1

b = -9

Explanation:

The function is given as :

`f(x)=3x^2+bx+4`

The axis of symmetry for this function is x = 3/2

It is required to find the value of b. The axis of symmetry of a parabola is a vertical line that intercepts its vertex at its horizontal coordinate. It can be given by :

`x=(-b)/(2a)`

Putting x = 3/2 and a = 3 we get :

`b=-2ax\\\\b=-2* 3* (3)/(2)\\\\b=-9`

So, the value of b is -9.