Answer:
1) sin Ф = -3/5
cos Ф = -4/5, sec Ф = -5/4
tan Ф = 3/4, cot Ф = 4/3.
Explanation:
The fact that cos Ф is negative shows that Ф is in either the second or the third quadrant. Also as csc Ф is also negative this makes Ф to be in the third quadrant.
csc Ф = -5/3 so sin Ф = 1 / csc Ф = -3/5.
Now the right triangle formed for sin = 3/5 has hypotenuse = 5 and one leg = 3 so the other leg , by Pythagaros, = √(5^2 - 3^2) = 4,
so cos Ф = -4/5 ( as we are in third quadrant).
sec Ф = 1 / cos Ф = -5/4.
tan Ф = sin Ф / cos Ф = -3/-4 = 3/4 ( as we are in the third quadrant).
cot Ф = 1 / tan Ф = 4/3.
Looks like the second part is incomplete?