Question

A 40.0-L sample of fluorine is heated from 90.0°C to 186.0°C. What volume will the sample occupy at the higher temperature?

Answer 1

The volume will be 82.67 L

Step-by-step explanation:

Charles's Law is the relationship between the volume and temperature of a certain amount of ideal gas. In this way, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

`(V)/(T) = k`

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

`(V1)/(T1) =(V2)/(T2)`

In this case, you know:

• V1= 40 L
• T1= 90 °C
• V2= ?
• T2= 186 °C

Replacing:

`(40L)/(90C) =(V2)/(186 C)`

Solving:

`V2=(40L)/(90C) *186 C`

V2= 82.67 L

The volume will be 82.67 L