Question

Write the equation of a line that is perpendicular to y=-0.3x+6 and passes through the point (3,-8)

Answer 1

y = 10/3x - 18

Explanation:

1. Take the reciprocal of the slope given to you, 3/10 -> 10/3

2. Write your new equation with the new slope in slope-intercept form: y=10/3x+b

3. Use the point given to find your y-intercept / b: -8 = (10/3)(3)+b

-8 = 10 + b

-18 = b

4. Plug b back into your new equation. y = 10/3x - 18