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Pleaseeee help me with number 2 and threee

Pleaseeee help me with number 2 and threee-example-1

1 Answer

3 votes

2.
x^2y^5√(x)

3.
\sqrt150} =
5\sqrt{6

30 and 5 are viable factors for 150

30 breaks down into 5 and 6

There are two 5s left and one 6.

So, the two fives go on the outside of the radical while the 6 goes on inside.

Therefore, it would be 5
\sqrt{6

User Moaz Saeed
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