Question

Pleaseeee help me with number 2 and threee

Answer 1

2.
`x^2y^5√(x)`

3.
`\sqrt150}` =
`5\sqrt{6`

30 and 5 are viable factors for 150

30 breaks down into 5 and 6

There are two 5s left and one 6.

So, the two fives go on the outside of the radical while the 6 goes on inside.

Therefore, it would be 5
`\sqrt{6`