Question

Write an equation in slope-intercept form of the line that is perpendicular to the line represented by 8x-4y+9=0 and passes through the point at (2, 3).

Answer 1

Explanation:

y - 3 = (-1/2)(x - 2)

Solve 8x-4y+9=0 for y so as to find the slope of this given line:

8x + 9 = 4y, or y = 2x + 9/4. The slope of the given line is 2. The slope of any line perpendicular to this one is the negative reciprocal of 2, which is -1/2.

Use the point-slope formula: y - k = m(x - h ). (h, k) is (2, 3) and m is -1/2.

Then we have: y - 3 = (-1/2)(x - 2)