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Gale the birthday clown is blowing up a fun spherical shaped balloon at a constant rate of 100 cubic inches per minute. How fast is the radius increasing when the sphere contains 50 cubic inches of clown breath

2 Answers

1 vote

Final answer:

To find the rate at which the radius is increasing when the sphere contains 50 cubic inches of clown breath, we can set up an equation using the volume formula for a sphere. Rearranging the equation and substituting the given volume, we can solve for the radius and calculate the rate of increase.

Step-by-step explanation:

We can use the formula for the volume of a sphere to solve this problem. The formula is:

V = (4/3)πr^3

where V is the volume and r is the radius of the sphere.

Given that the balloon is blowing up at a rate of 100 cubic inches per minute, we can set up an equation to find the rate at which the radius is increasing. Let's call it dr/dt:

100 = (4/3)πr^2(dr/dt)

To find dr/dt, we need to solve for it. Rearranging the equation, we get:

dr/dt = 100 / [(4/3)πr^2]

Substituting the given volume of 50 cubic inches, we can solve for the radius using the volume formula:

50 = (4/3)πr^3

Simplifying, we get:

r = (3/(4π))^(1/3) * 50^(1/3)

Finally, substituting the value of r back into the equation for dr/dt, we can find the rate at which the radius is increasing when the sphere contains 50 cubic inches of clown breath.

User Urania
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5 votes

Answer:

Step-by-step explanatio the way the question is phrased Is confusing

User Ashleigh Clayton
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