Question

A ball is thrown into the air. The function h(x) = −16(x − 2)2 + 72 models the height, in feet, of the ball after x seconds. What is the equation in standard form, and what is the maximum height of the ball?

A. h(x) = −16x2 + 32x + 72; 72 ft
B. h(x) = −16x2 − 32x + 72; 32 ft
C. h(x) = −16x2 − 64x + 32; 32 ft
D. h(x) = −16x2 + 64x + 8; 72 ft

Answer 1

h(x) = -16 xx + 64 x + 8 , in Standard Form

Vertex at (2, 72) maximum height at 72 feet

Explanation:

We have: h(x) = −16(x − 2)2 + 72

this function is in Vertex form.

the Standard form is when we expand out the expression.

h(x) = -16 *( x*x - 4x + 4) + 72

h(x) = -16 xx + 64 x - 64 + 72

h(x) = -16 xx + 64 x + 8

Vertex at (2, 72) maximum height at 72 feet