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Consider parallelogram ABCD, whose area is 162 sq. feet. If side AD equals 11 feet and the height DE equals 9 feet, find the perimeter of ABCD. Explain how you arrived at your final answer.

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Answer:

The perimeter of a parallelogram = 58 ft

Explanation:

A parallelogram is a quadrilateral with opposite sides parallel and equal in length. Opposite angles are also equal.

Area of parallelogram = base × height

Area = 162 ft²

area = bh

b = ?

h = 9 ft

162 = 9b

divide both sides by 9

b = 162/9

b = 18 ft

The perimeter of a parallelogram = 2(b + s)

where

b = base

s = the other sides

The perimeter of the parallelogram = 2(b + s)

The perimeter of the parallelogram = 2(18 + 11)

The perimeter of the parallelogram = 2(29)

The perimeter of the parallelogram = 58 ft

User Okera
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