Question

What is the pH of a 0.028M solution (pH=-log(M))

A) 3.56
B)2.88
C)1.55
D)1

Answer 1

ph =-log (28 x 10^-2)

= -(log 28 +log10^-2) ie using indices

= -(1.44+(-2) )

=-(-0.56)

= 0.56

=approximately (1) ans

Answer 2

C

Step-by-step explanation:

-log(0.028)=1.55