Answer:
Circuit A
Step-by-step explanation:
Let voltage of one battery be V
The circuit at the top has an overall voltage of
![V](https://img.qammunity.org/2021/formulas/chemistry/college/wbg4m7r8lis3maklqfhfgphf83yrv67bfw.png)
Circuit A is in series which means the overall voltage is
![V+V=2V](https://img.qammunity.org/2021/formulas/physics/high-school/tbgkabrnhdj245bvjj9hq0oxabuqx4kn4p.png)
Circuit B is the same as Circuit C where both are parallel to the bulb.
The overall voltage is
![(1)/(V)+ (1)/(V) = (2)/(V)](https://img.qammunity.org/2021/formulas/physics/high-school/xorykm2xfi10p38e594pgk1nkt3gw85f9z.png)
Circuit D will not work as the negative terminal of the battery are touching one another thus it impedes the electron flow in the circuit