Question

What would be the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg?

Answer 1

Answer: The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 2300 mm Hg = 3.02 atm (760mmHg=1atm)

V = Volume of gas = 15 L

n = number of moles = 0.6

R = gas constant =
`0.0821Latm/Kmol`

T =temperature = ?

`T=(PV)/(nR)`

`T=(3.02atm* 15L)/(0.0821Latm/K mol* 0.6mol)=920K`

Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K