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For a positive integers m, m=2m^2+1. What is the value of x if x=45,001?

For a positive integers m, m=2m^2+1. What is the value of x if x=45,001?-example-1

2 Answers

4 votes

Answer:

The value of x is 2,250.

Explanation:

The given expression is


2m^(2) +1

According to the problem, the expression is equal to 45,001 when uses x as variable, so


2x^(2) +1=45001

Solving for x, we have


2x^(2) =45001-1\\x^(2) =(4500)/(2)\\ x=2250

Therefore, the value of x is 2,250.

User Dipen Gajjar
by
7.6k points
3 votes

Answer:

150

Explanation:

Given for any positive integer m,

M = 2m²+1

If a value X = 45,001

Then applying this in the equation

X = 2x²+1

45,001 = 2x²+1

2x² = 45,001-1

2x² = 45,000

x² = 45000/2

x² = 22500

x = √22500

x = 150

The value of x is 150

User Catriona
by
8.8k points

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