Question

Sin(90-x)=cos(x) use sum or difference formula to solve​

Answer 1

`sin(90-x)=cos(x)`

So,

`sin(a-b)=sin(a)cos(b)-cos(a)sin(b)`

`sin(90\º-x)=sin(90\º)cos(x)-cos(90\º)sin(x)`

Once,
`sin90\º=1` and
`cos(90\º)=0`

`sin(90\º-x)=1cos(x)-0sin(x)`

`sin(90\º-x)=cos(x)`