Question

A number from 0 to 9 is randomly selected and then a letter from A to D is randomly selected. What is the probability that the number 3 and a consonant are selected? Express as a fraction in simplest form.

Answer 1

The probability of selecting a number 3 and a consonant is 3/40.

Step-by-step explanation:

To find the probability that a number 3 and a consonant are selected, we need to first determine the total number of possible outcomes.

There are 10 numbers from 0 to 9 and 4 letters from A to D, so the total number of outcomes is 10 × 4 = 40.

Next, we need to determine the number of favorable outcomes, which is the number of times a number 3 and a consonant are selected.

There is only 1 number 3 and 3 consonants, so there is a total of 1 × 3 = 3 favorable outcomes.

Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of outcomes: 3/40. This fraction cannot be simplified further, so the probability is 3/40.

Answer 2

3/20

Step-by-step explanation:

First we must get the total amount of possibilities.

We have ten numbers(0 included) and 4 letters. 10 * 4 = 40, so 40 total possibilities.

Now, let's see how many possibilities we can have for this.

Consonants in the 4 letters are B, C, D. This means we have 3 possibilities, but we ACTUALLy have 6 since it could b then 3, or 3 then b for all the letters.

So, we end up having 6/40 which simplifies in to 3/20