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Explain why the initial value of any function of the form
fx) = a(b') is equal to a.​

1 Answer

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Answer:

the zero power of anything (except 0) is 1, so ab^0 = a·1 = a

Explanation:

We assume you're concerned with the exponential function ...

f(x) = a(b^x)

The factor b^x will be b^0 when x=0. This is generally what we mean when we say "initial value."

The value of b^0 is always 1 (for any non-zero value of b). So the initial value of the function is ...

f(0) = a(b^0) = a(1) = a

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