Question

Write an equation in point-slope form of the line that passes through the point (-6,6) and has a slope of m=3/2

Answer 1

y-6=(3/2)(x+6)

Explanation:

Given:

• slope = m = 3/2
• point = (x1,y1) = (-6,6)

Point-Slope:

`\displaystyle \large{y-y_1=m(x-x_1)}`

Substitute m = 3/2, x1 = -6 and y1 = 6:

`\displaystyle \large{y-6=(3)/(2)[x-(-6)]}\\\displaystyle \large{y-6=(3)/(2)(x+6)}`

Therefore, the equation is y-6=3/2(x+6)