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Help me with this question

Help me with this question-example-1
User Kechit Goyal
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Step-by-step explanation:

Escape velocity is the point at which the kinetic energy is equal to the gravitational potential energy.

KE = PE

½ mv² = mgh

½ mv² = m (GM/r²) (r)

½ mv² = GMm/r

½ v² = GM/r

v = √(2GM/r)

The escape velocity is independent of the mass of the spacecraft. So the escape velocity will be the same for both X and Y.

User Vanpersil
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