Answer: ∠BAF≅∠DEF
Explanation:
In the given figure triangle BAE is congruent to triangle DEA i.e. ΔBAE ≅ ΔDEA.
We know that if two triangles are congruent then their corresponding angles are congruent.
Since, ΔBAE ≅ ΔDEA, the by CPCTC [congruent parts of congruent triangles are congruent]
∠BAE≅∠DEA
Since F is a point on AE
So, ∠BAE≅∠DEA
⇒ ∠BAF≅∠DEF