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H = -5t2 + 30t + 10
a) What is the Rocket's maximum height?

User Andrej K
by
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1 Answer

0 votes

Answer:

The maximum height is 55

Explanation:

Step 1: Find the derivative with respect to t


-5t^2 + 30t + 10


-5*2t + 30


-10t+30

Step 2: Solve for t


-10t + 30 - 30 = 0 - 30


-10t / -10 = -30 / -10


t = 3

Step 3: Plug in 3 for t in the original equation


h = -5(3)^2 + 30(3) + 10


h = -5(9) + 90 + 10


h = -45+90+10


h = 45 + 10


h = 55

Answer: The maximum height is 55

User McStretch
by
7.7k points
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