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Write an equation in point-slope form of the line that passes through the point (-6,6) and has a slope of m=3/2

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User Yvolk
by
8.0k points

1 Answer

6 votes

Answer:


y-6=(3)/(2) (x+6)

Explanation:

Hi there!

We are given a point (-6, 6) and a slope of
(3)/(2)

We want to write the equation of the line that contains this point and slope in point-slope form

Point-slope form is written as
y-y_1=m(x-x_1), where m is the slope and
(x_1, y_1) is a point

As we are already given everything we need, we can simply substitute the values into the formula

Starting with the slope, substitute 3/2 as m into the equation:


y-y_1=(3)/(2) (x-x_1)

Now substitute -6 as
x_1 and 6 as
y_1


y-6=(3)/(2) (x--6)

Simplify:


y-6=(3)/(2) (x+6)

Hope this helps!

User BrandonMayU
by
8.4k points

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