206k views
0 votes
What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?

3
3RootIndex 3 StartRoot 4 EndRoot
6RootIndex 3 StartRoot 3 EndRoot
27

User TheChetan
by
3.4k points

2 Answers

5 votes

Answer:

B.

Explanation:

User Ravindra S
by
3.6k points
6 votes

Answer:

The required simplified base would be 3∛4

Explanation:

Given exponential function that:


f(x)=(1)/(4)(\sqrt[3]{108})^x

As we can see, 108 is the base of the exponential function with the form:

f(x) = a
b^(x)

So, we can factor 108 = 2 × 2 × 3 × 3 × 3

<=> 108 = 4 × 3³

Hence,
\sqrt[3]{108} = \sqrt[3]{4* 3^3}

So we have:


\sqrt[3]{108}=\sqrt[3]{4}* \sqrt[3](3^3)

<=>
\sqrt[3]{108}=\sqrt[3]{4}* (3^3)^(1)/(3)

<=>
\sqrt[3]{108}=\sqrt[3]{4}* 3^{3* (1)/(3)}

<=>
\sqrt[3]{108}=3\sqrt[3]{4}

Hence, the required simplified base would be 3∛4

User Brian MacKay
by
3.4k points