Question

Find the vertex, zero and y-intercept of the graph of y=x^2 -6x+8

Answer 1

vertex: (3, -1) and zeros: x = 4, x = 2 and y-int: y = -1

Explanation:

y = xx - 6x + 8

y = (x - 4)(x - 2)

since -4 * -2 = 8

and -4 + -2 = -6

so roots are x = 4 and x = 2

y = xx - 6x + 9 - 9 + 8

y = (x - 3)^2 - 1

vertex: (3, -1)

y-int: y = -1