Question

Line p passes through points (9, 7) and (6, 3). Line q is perpendicular to p. What is the slope of line q?

Answer 1

m = -3/4

Explanation:

Going from (6, 3) to (9, 7), x (the run) increases by 3 and y (the rise) increases by 4. Thus, the slope of the line connecting these two points is m = rise/run = 4/3.

Two lines are perpendicular if their slopes are negative reciprocals of one another. In this case, the slope of q is the negative reciprocal of 4/3, and is

m = -3/4.