Question

Length of the hypotenuse of the triangle to the nearest tenth of a metre

Answer 1

Answer:2.4

Explanation:

sin55=2 ➗ h

0.8192=2 ➗ h

Cross multiplying we get

0.8192 x h=2

Divide both sides by 0.8192

(0.8192xh)/0.8192=2/0.8192

h=2.4

Answer 2

The length of the hypotenuse is 2.4m

Explanation:

well to start we have to know the relationship between angles, legs and the hypotenuse

α = 55°

o: opposite = 2.0m

h: hypotenuse

sin α = o/h

cos α= a/h

tan α = o/a

we see that it has (angle, hypotenuse, opposite)

we look at which meets those data between the sine, cosine and tangent

is the sine

sin α = o/ah

Now we replace the values ​​and solve

sin 55 = 2.0/h

0.81915 = 2.0/h

h = 2.0 / 0.81915

h = 2.4415 m

round to the nearest tenth

h = 2.4415 = 2.4 m

The length of the hypotenuse is 2.4m