151k views
0 votes
Length of the hypotenuse of the triangle to the nearest tenth of a metre

Length of the hypotenuse of the triangle to the nearest tenth of a metre-example-1
User Mesh
by
8.6k points

2 Answers

4 votes

Answer:2.4

Explanation:

sin55=2 ➗ h

0.8192=2 ➗ h

Cross multiplying we get

0.8192 x h=2

Divide both sides by 0.8192

(0.8192xh)/0.8192=2/0.8192

h=2.4

User Alec Segal
by
8.3k points
2 votes

Answer:

The length of the hypotenuse is 2.4m

Explanation:

well to start we have to know the relationship between angles, legs and the hypotenuse

α = 55°

o: opposite = 2.0m

h: hypotenuse

sin α = o/h

cos α= a/h

tan α = o/a

we see that it has (angle, hypotenuse, opposite)

we look at which meets those data between the sine, cosine and tangent

is the sine

sin α = o/ah

Now we replace the values ​​and solve

sin 55 = 2.0/h

0.81915 = 2.0/h

h = 2.0 / 0.81915

h = 2.4415 m

round to the nearest tenth

h = 2.4415 = 2.4 m

The length of the hypotenuse is 2.4m

User Kyle Slattery
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories